(x^2-2x-15)(4x+5)=0

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Solution for (x^2-2x-15)(4x+5)=0 equation: 


Simplifying
(x2 + -2x + -15)(4x + 5) = 0

Reorder the terms:
(-15 + -2x + x2)(4x + 5) = 0

Reorder the terms:
(-15 + -2x + x2)(5 + 4x) = 0

Multiply (-15 + -2x + x2) * (5 + 4x)
(-15(5 + 4x) + -2x * (5 + 4x) + x2(5 + 4x)) = 0
((5 * -15 + 4x * -15) + -2x * (5 + 4x) + x2(5 + 4x)) = 0
((-75 + -60x) + -2x * (5 + 4x) + x2(5 + 4x)) = 0
(-75 + -60x + (5 * -2x + 4x * -2x) + x2(5 + 4x)) = 0
(-75 + -60x + (-10x + -8x2) + x2(5 + 4x)) = 0
(-75 + -60x + -10x + -8x2 + (5 * x2 + 4x * x2)) = 0
(-75 + -60x + -10x + -8x2 + (5x2 + 4x3)) = 0

Combine like terms: -60x + -10x = -70x
(-75 + -70x + -8x2 + 5x2 + 4x3) = 0

Combine like terms: -8x2 + 5x2 = -3x2
(-75 + -70x + -3x2 + 4x3) = 0

Solving
-75 + -70x + -3x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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